14. September 2016 um 18:26 #1 a) lim 2x^2-18:x+3 x->-3b) lim x^2-7x+10:x-5 x->5c) lim x^2-x0^2:x-x0 x->x0
18. September 2016 um 19:35 #2 lim x→ -3 (2x2-1 / (x+3)(2·(-3 + h)2 - 1/((-3 + h) + 3) = 2·h - 12lim x→ 5 (x2-7x+10) / (x-5)((5 + h)2 - 7·(5 + h) + 10)/((5 + h) - 5) = h + 3lim x→ 1 (x2-x) / (x-1)((1 + h)2 - (1 + h))/((1 + h) - 1) = h + 1lim x→ x0 (x2-x02) / (x-x0)((x0 + h)2 - x02)/((x0 + h) - x0) = 2·x0 + h
