Solution trisecting (n-sections) and n-proper construction of the polygon using divider and straightedge.
The ball shall be awarded in two equal parts, obtained half contains two areas, the circle (represents a planar geometry) and a semi-sphere (represents spherical geometry), the circle is the boundary between the circuit and semi-sphere
View photo (below)
CIRCLE
within a given arbitrary angle BAC,
straightedge (straightedge is flexible, it can draw on a sphere) along the BA to extend the circle to give the point D
SPHERE
straightedge connect points B and D, you get the curve BD
straightedge and divider - a procedure divisions curve into two equal parts is the same as the process of division shall exceed the level in two equal parts, we get the point E
straightedge - connect points C and E and get the curve CE
Proportion longer exists in plane geometry, I found that the process can be applied to the sphere
choose point G
divider EC, from point G we get a point H
divider EC, from point H we get a point I
divider EC, from point E twe get a point J
divider EC, from point J get the point K
divider EC, from point K get the point L
straightedge point L and point I and connect, we get curve LI
EG divider, from the point L we get a point P
EG divider, from the point P and get the point O
straightedge join the dots E and P and proceed to the circle, we get the point Q
straightedge merge points E and O and proceed to the circle, we get the point R
CIRCLE
straightedge connect point A and point Q, we get along AQ
straightedge connect point A and point R, we get along AR
these have carried out the production of a given trisection angle, is obtained from the rest of the (n-section, a regular n-polygon) ...
Now proclaim everywhere that I decided 2- millennium math problems